-0.00006x^2-0.04x+200=0

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Solution for -0.00006x^2-0.04x+200=0 equation:



-0.00006x^2-0.04x+200=0
We add all the numbers together, and all the variables
-5x^2-0.04x+200-6.0E=0
We add all the numbers together, and all the variables
-5x^2-0.04x+183.69030902925=0
a = -5; b = -0.04; c = +183.69030902925;
Δ = b2-4ac
Δ = -0.042-4·(-5)·183.69030902925
Δ = 3673.807780585
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.04)-\sqrt{3673.807780585}}{2*-5}=\frac{0.04-\sqrt{3673.807780585}}{-10} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.04)+\sqrt{3673.807780585}}{2*-5}=\frac{0.04+\sqrt{3673.807780585}}{-10} $

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